Figure 3.1:
Taken from Figs.6 and 7 of Kennicutt (1998).
Left: The
-axis means the total (HI+H
) gas density and the
-axis does the global star formation rate.
Right: The
-axis means the total (HI+H
) gas density divided by the orbital time-scale.
The
-axis is the same.
 |
The star formation rate is estimated by the intensity of H
emission
(Kennicutt, Tamblyn, & Congdon 1994) as
 |
(3.2) |
which is used for normal galaxies.
While in the starburst galaxies which show much larger star formation rate than the normal galaxies,
FIR luminosity seems a better indicator of star formation rate
 |
(3.3) |
Kennicutt (1998) summarized the relation between SFRs and the surface gas densities [Fig.3.1 (left)]
for 61 normal spiral and 36 infrared-selected starburst galaxies.
As seen in Figure 3.1,
the star formation rate averaged over a galaxy (
),
which is called the global star formation rate,
is well correlated to the average gas surface density
.
He gave the power of the global Schmidt law as
.
That is,
 |
(3.4) |
The fact that the power is not far from 3/2 seems to be explained as follows:
Star formation rate should be proportional to the gas density (
) but it should also be inversely proportional to the
time scale of forming stars in respective gas clouds, which is essentially the free-fall time scale.
Remember the fact that the free-fall time given in equation (2.26) is proportional to
.
Therefore
 |
(3.5) |
where
and
are the volume densities of gas and star formation.
He found another correlation between a quantity of gas surface density divided by the
orbital period of galactic rotation and the star formation rate [Fig.3.1 (right)].
Although the actual slope is equal to 0.9 instead of 1,
the correlation in Fig.3.1(right) is well expressed as
 |
(3.6) |
where
represents the angular speed of galactic rotation.
This means that 21 % of the gas mass is processed to form stars per orbit.
These two correlations [eqs. (3.4) and (3.6)]
implicitly ask another relation of
.
Kohji Tomisaka
2012-10-03